How many beer cans

rubber side up · May 2007

could i fit in a room that measures:
part A) L:196cm x D:81cm x H:230cm
part

L:244cm x D:276cm x H: 230cm

the beer can size is roughly L:6.5cm x

6.5cm x H:15cm

i worked it out as 25,560 cans. but a friend managed to get just over 30 thousand. so i'm at a loss. who is right?

<hr noshade size="1"><center><blockquote id="quote">quote:<hr height="1" noshade id="quote">Originally posted by EvilAlex

Something round here tastes bad. Could be plain old bad taste.
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newmember · May 2007

gooooooogle will know.

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extreme__dude · May 2007

sh!t loads??

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newmember · May 2007

<blockquote id="quote">quote:<hr height="1" noshade id="quote">Originally posted by extreme__dude

sh!t loads??

<center>pinkbike</center>
<center>new frame [:D]</center>
<hr height="1" noshade id="quote"></blockquote id="quote">

yeah that sounds about right. oh and why are you trying to work this out?

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robfox · May 2007

30202,13017751479 is the answer so your mate was right [;)]

rob

Cannondale Chase
Transition Bottlerocket

John · May 2007

30187?

Working to 2 decemals that is.

havent fallen off,
im just having a rest

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neil h · May 2007

i make it 30202

so yea, thats a lot of beer. though alarmingly i'm almost bored enough to work out how much it would cost to acquire that much beer.

rubber side up · May 2007

<blockquote id="quote">quote:<hr height="1" noshade id="quote">Originally posted by newmember

oh and why are you trying to work this out?
<hr height="1" noshade id="quote"></blockquote id="quote">

I'm that bored. needed something that involves thinking, to take my mind off the enormous amounts of pain my back is causing me.

<hr noshade size="1"><center><blockquote id="quote">quote:<hr height="1" noshade id="quote">Originally posted by EvilAlex

Something round here tastes bad. Could be plain old bad taste.
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rubber side up · May 2007

<blockquote id="quote">quote:<hr height="1" noshade id="quote">Originally posted by neil h

i make it 30202

so yea, thats a lot of beer. though alarmingly i'm almost bored enough to work out how much it would cost to acquire that much beer.
<hr height="1" noshade id="quote"></blockquote id="quote">

did you round the number up or down though?

I did it the (seemingly) simple way. by working out how many cans would fit along one wall, then multiply that by the number along the other wall. giving the amount of cans to cover the floor. then multiply that by the amount of cans that could stand on end from floor to ceiling. however i have no idea if that is right or not. its been a while since i did maths of any description, and i used to suck at it while at school [xx(]

<hr noshade size="1"><center><blockquote id="quote">quote:<hr height="1" noshade id="quote">Originally posted by EvilAlex

Something round here tastes bad. Could be plain old bad taste.
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RetroYetiRigid · May 2007

More than I could drink in an hour ! [:P]

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neil h · May 2007

i worked out that volume of a can, then the volume of the 2 rooms. Then divided the total volume of the rooms by the volume of the can.

and i rounded it down because you can't round it up as there isn't actually any space for the .8 of a car you would be rounding up.

anto164 · May 2007

i worked it out as... 30202.130177514792899408284023669 cans, so thats 30202 cans.

i worked out the volume of the rooms, added them together, then worked out the volume of the can, and divided the two

 MON BICI!!
myspaz

John · May 2007

<blockquote id="quote">quote:<hr height="1" noshade id="quote">Originally posted by anto164

i worked out the volume of the rooms, added them together, then worked out the volume of the can, and divided the two
<hr height="1" noshade id="quote"></blockquote id="quote">

But then you adding the volumes of the 2 rooms together means your fitting them into one big room not 2 smaller parts, Which would change the number you could fit down each wall and up to the celing,

I did the 2 rooms seperately and then added the cans in each room up, Was that wrong?

havent fallen off,
im just having a rest

Updated [:D] Glory Jackal

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neil h · May 2007

well presumably the dimensions given for the rooms were internal, hence it doesnt really matter whether you add the 2 or not.

rubber side up · May 2007

the room is L shaped, the smaller part branching off from the bigger area. no walls or anything [:)]

<hr noshade size="1"><center><blockquote id="quote">quote:<hr height="1" noshade id="quote">Originally posted by EvilAlex

Something round here tastes bad. Could be plain old bad taste.
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Gibbon on an Orange · May 2007

Have people taken into account that the cans are round, and will leave space between eachother?

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anto164 · May 2007

<blockquote id="quote">quote:<hr height="1" noshade id="quote">Originally posted by neil h

well presumably the dimensions given for the rooms were internal, hence it doesnt really matter whether you add the 2 or not.
<hr height="1" noshade id="quote"></blockquote id="quote">

not quite, as you're treating them as two seperate rooms. the beer cans dont actually fit in fully, so you will be losing spare volume.

what the question should be, is the cans have a radius of 3.25cm, and a height of 15cm, that would have confused many people, as im guessing people would use [Pi*r(squared)]* height to find the volume, it would make for some funny workings out.

<blockquote id="quote">quote:<hr height="1" noshade id="quote">Originally posted by Gibbon on an Orange

Have people taken into account that the cans are round, and will leave space between eachother?<hr height="1" noshade id="quote"></blockquote id="quote">

you dont need to, as the question is taking into account that the cans are not cylindrical, more like a cuboid (is that what a 3d rectangle is called?).

 MON BICI!!
myspaz

rubber side up · May 2007

<blockquote id="quote">quote:<hr height="1" noshade id="quote">Originally posted by Gibbon on an Orange

Have people taken into account that the cans are round, and will leave space between eachother?

<center>
Zoo Pitbull

Turner DHR</center>
<hr height="1" noshade id="quote"></blockquote id="quote">

we turned the cans into a cube shape.

<hr noshade size="1"><center><blockquote id="quote">quote:<hr height="1" noshade id="quote">Originally posted by EvilAlex

Something round here tastes bad. Could be plain old bad taste.
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neil h · May 2007

yea. i took the volume of the can as being its equivalent as a cuboid. though you would get a different value if you used the value of an actual can (500cubic Cm) how ever this would be the volume of a liquid inside the can, rather than the equivalent space occupied by the cna itself.

if that makes sense.

Matt · May 2007

I'm confused. You want the answer to room one or two?

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Chaparral

rubber side up · May 2007

its only one room. so add the final figures together [:)]

<hr noshade size="1"><center><blockquote id="quote">quote:<hr height="1" noshade id="quote">Originally posted by EvilAlex

Something round here tastes bad. Could be plain old bad taste.
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elmotheewokking · May 2007

Forty two.

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<blockquote id="quote">quote:<hr height="1" noshade id="quote">Originally posted by i_used_2b_fukpigonabike

at least it hasn't rashed like my groin.
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Super Nuts4fsr · May 2007

<blockquote id="quote">quote:<hr height="1" noshade id="quote">Originally posted by elmotheewokking

Forty two.

<center>
<blockquote id="quote">quote:<hr height="1" noshade id="quote">Originally posted by i_used_2b_fukpigonabike

at least it hasn't rashed like my groin.
<hr height="1" noshade id="quote"></blockquote id="quote"></center>
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Shadow_Conspiracy · May 2007

The cans would tessellate though, meaning if you put them in a staggered formation, they would fit closer together...

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How many beer cans

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